Programs to print the spiral pattern using numbers are given here. If the size of this pattern is s, the pattern is completed after printing $s^2$.
1. Program & output to print the spiral pattern
1.1. C Program & output to print the spiral pattern
Code has been copied
/********************** alphabetacoder.com C program for a spiral pattern using numbers ***********************/ #include <stdio.h> #define SIZE 10 int main() { // declare variables int pattern[SIZE][SIZE] = {0}; int i, j, m, n, p, q, s, num; // take input printf("Enter the size of the pattern: "); scanf("%d", & s); // initialize num = 1; // starting number i = 0; // 2d array row index j = 0; // 2d array column index m = 0; // to store row index lower limit n = s - 1; // to store row index upper limit p = 0; // to store column index lower limit q = s - 1; // to store column index upper limit // fill the array to create patern. // stop when n > s * s while (num <= s * s) { // fill horizontally left to right for (j = p; j <= q; j++) { pattern[m][j] = num; num++; } // update row index lower limit m++; // fill vertically top to bottom for (i = m; i <= n; i++) { pattern[i][q] = num; num++; } // update column index upper limit q--; // fill horizontally right to left for (j = q; j >= p; j--) { pattern[n][j] = num; num++; } // update row index upper limit n--; // fill vertically bottom to top for (i = n; i >= m; i--) { pattern[i][p] = num; num++; } // update column index lower limit p++; } // new line printf("\n"); // display the pattern for (i = 0; i < s; i++) { for (j = 0; j < s; j++) { // print value printf("%d\t", pattern[i][j]); } // new line printf("\n"); } return 0; }
Output
Case 1:
Enter the size of the pattern: 5
1 2 3 4 5
16 17 18 19 6
15 24 25 20 7
14 23 22 21 8
13 12 11 10 9
Case 2:
Enter the size of the pattern: 10
1 2 3 4 5 6 7 8 9 10
36 37 38 39 40 41 42 43 44 11
35 64 65 66 67 68 69 70 45 12
34 63 84 85 86 87 88 71 46 13
33 62 83 96 97 98 89 72 47 14
32 61 82 95 100 99 90 73 48 15
31 60 81 94 93 92 91 74 49 16
30 59 80 79 78 77 76 75 50 17
29 58 57 56 55 54 53 52 51 18
28 27 26 25 24 23 22 21 20 19
1.2. C++ Program & output to print the spiral pattern
Code has been copied
/********************** alphabetacoder.com C++ program for a spiral pattern using numbers ***********************/ #include <iostream> #define SIZE 10 using namespace std; int main() { // declare variables int pattern[SIZE][SIZE] = {0}; int i, j, m, n, p, q, s, num; // take input cout << "Enter the size of the pattern: "; cin >> s; // initialize num = 1; // starting number i = 0; // 2d array row index j = 0; // 2d array column index m = 0; // to store row index lower limit n = s - 1; // to store row index upper limit p = 0; // to store column index lower limit q = s - 1; // to store column index upper limit // fill the array to create patern. // stop when n > s * s while (num <= s * s) { // fill horizontally left to right for (j = p; j <= q; j++) { pattern[m][j] = num; num++; } // update row index lower limit m++; // fill vertically top to bottom for (i = m; i <= n; i++) { pattern[i][q] = num; num++; } // update column index upper limit q--; // fill horizontally right to left for (j = q; j >= p; j--) { pattern[n][j] = num; num++; } // update row index upper limit n--; // fill vertically bottom to top for (i = n; i >= m; i--) { pattern[i][p] = num; num++; } // update column index lower limit p++; } // new line cout << endl; // display the pattern for (i = 0; i < s; i++) { for (j = 0; j < s; j++) { // print value cout << pattern[i][j] << "\t"; } // new line cout << endl; } return 0; }
Output
Enter the size of the pattern: 6
1 2 3 4 5 6
20 21 22 23 24 7
19 32 33 34 25 8
18 31 36 35 26 9
17 30 29 28 27 10
16 15 14 13 12 11
1.3. Java Program & output to print the spiral pattern
Code has been copied
/************************* alphabetacoder.com Java program for a spiral pattern using numbers **************************/ import java.util.Scanner; class Main { public static void main(String[] args) { // declare instance of Scanner class Scanner sc = new Scanner(System.in); // declare variables int i, j, m, n, p, q, s, num; // take input System.out.print("Enter the size of the pattern: "); s = sc.nextInt(); // declare 2D array int[][] pattern = new int[s][s]; // initialize num = 1; // starting number i = 0; // 2d array row index j = 0; // 2d array column index m = 0; // to store row index lower limit n = s - 1; // to store row index upper limit p = 0; // to store column index lower limit q = s - 1; // to store column index upper limit // fill the array to create patern. // stop when n > s * s while (num <= s * s) { // fill horizontally left to right for (j = p; j <= q; j++) { pattern[m][j] = num; num++; } // update row index lower limit m++; // fill vertically top to bottom for (i = m; i <= n; i++) { pattern[i][q] = num; num++; } // update column index upper limit q--; // fill horizontally right to left for (j = q; j >= p; j--) { pattern[n][j] = num; num++; } // update row index upper limit n--; // fill vertically bottom to top for (i = n; i >= m; i--) { pattern[i][p] = num; num++; } // update column index lower limit p++; } // new line System.out.println(""); // display the pattern for (i = 0; i < s; i++) { for (j = 0; j < s; j++) { // print value System.out.print(pattern[i][j] + "\t"); } // new line System.out.println(""); } } }
Output
Enter the size of the pattern: 4
1 2 3 4
12 13 14 5
11 16 15 6
10 9 8 7
1.4. Python Program & output to print the spiral pattern
Code has been copied
#**************************** # alphabetacoder.com #Python program for a spiral #pattern using numbers #**************************** # take input s = int(input("Enter the size of the pattern: ")) # declare 2D array pattern = [[0 for i in range(s)] for j in range(s)] # initialize num = 1 # starting number i = 0 # 2d array row index j = 0 # 2d array column index m = 0 # to store row index lower limit n = s - 1 # to store row index upper limit p = 0 # to store column index lower limit q = s - 1 # to store column index upper limit # fill the array to create patern. # stop when n > s * s while num <= s * s: # fill horizontally left to right for j in range(p, q + 1): pattern[m][j] = num num = num + 1 # update row index lower limit m = m + 1 # fill vertically top to bottom for i in range(m, n + 1): pattern[i][q] = num num = num + 1 # update column index upper limit q = q - 1 # fill horizontally right to left for j in range(q, p - 1, -1): pattern[n][j] = num num = num + 1 # update row index upper limit n = n - 1 # fill vertically bottom to top for i in range(n, m - 1, -1): pattern[i][p] = num num = num + 1 # update column index lower limit p = p + 1 # new line print(""); # display the pattern for i in range(0, s): for j in range(0, s): # print value print(pattern[i][j], end = "\t") # new line print("")
Output
Enter the size of the pattern: 7
1 2 3 4 5 6 7
24 25 26 27 28 29 8
23 40 41 42 43 30 9
22 39 48 49 44 31 10
21 38 47 46 45 32 11
20 37 36 35 34 33 12
19 18 17 16 15 14 13
1.5. C# Program & output to print the spiral pattern
Code has been copied
/********************** alphabetacoder.com C# program for a spiral pattern using numbers ***********************/ using System; namespace Spiral { class Program { static void Main(string[] args) { // declare variables int i, j, m, n, p, q, s, num; // take input Console.Write("Enter the size of the pattern: "); s = Convert.ToInt32(Console.ReadLine()); // declare a 2D array variables int[, ] pattern = new int[s, s]; // initialize num = 1; // starting number i = 0; // 2d array row index j = 0; // 2d array column index m = 0; // to store row index lower limit n = s - 1; // to store row index upper limit p = 0; // to store column index lower limit q = s - 1; // to store column index upper limit // fill the array to create patern. // stop when n > s * s while (num <= s * s) { // fill horizontally left to right for (j = p; j <= q; j++) { pattern[m, j] = num; num++; } // update row index lower limit m++; // fill vertically top to bottom for (i = m; i <= n; i++) { pattern[i, q] = num; num++; } // update column index upper limit q--; // fill horizontally right to left for (j = q; j >= p; j--) { pattern[n, j] = num; num++; } // update row index upper limit n--; // fill vertically bottom to top for (i = n; i >= m; i--) { pattern[i, p] = num; num++; } // update column index lower limit p++; } // new line Console.WriteLine(""); // display the pattern for (i = 0; i < s; i++) { for (j = 0; j < s; j++) { // print value Console.Write("\t" + pattern[i, j]); } // new line Console.WriteLine(""); } // wait for user to press any key Console.ReadKey(); } } }
Output
Enter the size of the pattern: 9
1 2 3 4 5 6 7 8 9
32 33 34 35 36 37 38 39 10
31 56 57 58 59 60 61 40 11
30 55 72 73 74 75 62 41 12
29 54 71 80 81 76 63 42 13
28 53 70 79 78 77 64 43 14
27 52 69 68 67 66 65 44 15
26 51 50 49 48 47 46 45 16
25 24 23 22 21 20 19 18 17