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C++ Program to Print All Numbers in a Range

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Print all numbers in a range

C++ programs to print all the numbers in a range have been shown here. Both of the iterative and recursive approaches have been covered.






1. Algorithm to Print All numbers in a range


1. Take input of two numbers n1, n2 as range limit.

2. Set another variable i=n1

3. Iterate i from n1 to n2 by incrementing 1

4. Print value of i in each iteration




2. Pseudocode to Print All numbers in a range


Input : Two integer numbers $n_1, n_2$

Output : All the integer numbers from $n_1$ to $n_2$

1. Procedure printAll($n_1$, $n_2$):

2. $i\leftarrow n_1$

3. Repeat until $i > n_2$

4. Print $i$

5. $i \leftarrow i+1$

6. End Procedure





3. Time complexity to Print All numbers in a range


Time Complexity: O(n)

Here, $n$ is the no. of terms in the given range.





4. C++ Program & Output to Print All Integer numbers in a range using Iteration

Code has been copied
/*********************************************
            alphabetacoder.com
 C++ program to print all integer numbers in 
 a given range using iterative approach
**********************************************/

#include <iostream>

using namespace std;

int main() {
    // declare variables
    int n1, n2, i;

    //take input of the ranges
    cout << "Enter the lower limit = ";
    cin >> n1;
    cout << "Enter the upper limit = ";
    cin >> n2;

    // iterate from n1 to n2 and print the numbers
    cout << "Numbers in the range: ";
    for (i = n1; i <= n2; i++)
        cout << i << " ";

    return 0;
}

Output

Enter the lower limit = 15

Enter the upper limit = 30

Numbers in the range: 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30




5. C++ Program & Output to Print All Integer numbers in a range using Recursion

Code has been copied
/**********************************************
            alphabetacoder.com
 C++ program to print all integer numbers in
 a given range using a recursive approach
*********************************************/

#include <iostream>

using namespace std;

// recursive function
void printNumbers(int n1, int n2) {
    //condition for calling
    if (n2 > n1)
        printNumbers(n1, n2 - 1);
    // print current numbers
    cout << n2 << " ";
}

int main() {
    // declare variables
    int n1, n2;
    //take input of the ranges
    cout << "Enter the lower limit = ";
    cin >> n1;
    cout << "Enter the upper limit = ";
    cin >> n2;

    cout << "Numbers in the range: ";
    // call the recursive function to print
    // all the integer numbers in a range
    printNumbers(n1, n2);

    return 0;
}

Output

Enter the lower limit = 10

Enter the upper limit = 15

Numbers in the range: 10 11 12 13 14 15




6. C++ Program & Output to Print All Float numbers with specific interval in a range using Iteration

Code has been copied
/********************************************
            alphabetacoder.com
 C++ program to print all float numbers with
 specific interval in a given range
*********************************************/

#include <iostream>

using namespace std;

int main() {
    // declare variables
    double n1, n2, in, i;
    //take input of the ranges
    cout << "Enter the lower limit = ";
    cin >> n1;
    cout << "Enter the upper limit = ";
    cin >> n2;

    // take input of step
    cout << "Enter the value of interval = ";
    cin >> in;

    cout << "Numbers in the range: ";
    // dislay all numbers between n1 and n2
    // with given interval
    for (i = n1; i <= n2; i += in)
        cout << i << " ";

    return 0;
}

Output

Enter the lower limit = 10

Enter the upper limit = 25

Enter the value of interval = 0.5

Numbers in the range: 15 15.5 16 16.5 17 17.5 18 18.5 19 19.5 20 20.5 21 21.5 22 22.5 23 23.5 24 24.5 25




7. C++ Program & Output to Print All Float numbers with specific interval in a range using Recursion

Code has been copied
/*****************************************************
            	alphabetacoder.com
 C++ program to print all float numbers with specific
 interval in a given range using recursive approach
******************************************************/

#include <iostream>

using namespace std;

// recursive function
void printNumbers(double n1, double n2, double in ) {
    //condition for calling
    if (n2 > n1)
        printNumbers(n1, n2 - in, in);
    // print current number
    cout << n2 << " ";
}

int main() {
    // declare variables
    double n1, n2, in;
    //take input of the ranges
    cout << "Enter the lower limit = ";
    cin >> n1;
    cout << "Enter the upper limit = ";
    cin >> n2;

    // take input of step
    cout << "Enter the value of interval = ";
    cin >> in;

    printf("Numbers in the range: ");
    // call the recursive function to print
    // all the float numbers in input range
    printNumbers(n1, n2, in);

    return 0;
}

Output

Enter the lower limit = 100

Enter the upper limit = 101

Enter the value of interval = 0.07

Numbers in the range: 99.95 100.02 100.09 100.16 100.23 100.3 100.37 100.44 100.51 100.58 100.65 100.72 100.79 100.86 100.93 101




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