C# program for array rotation has been shown here. An array rotation is described as the rotation of array elements to either left or right by k positions.

Example 1: Left rotation

Given array A[] = {10, 20, 30, 40, 50, 60}, k = 2

Rotate elements of A[] by 1 position to the left.

=>A[] = {20, 30, 40, 50, 60, 10}

Again rotate elements of A[] by 1 position to the left.

=>A[] = {30, 40, 50, 60, 10, 20}

So, array A[] after left rotation by 2 positions: {30, 40, 50, 60, 10, 20}

Example 2: Right rotation

Given array A[] = {10, 20, 30, 40, 50, 60}, k = 2

Rotate elements of A[] by 1 position to the right.

=>A[] = {60, 10, 20, 30, 40, 50}

Again rotate elements of A[] by 1 position to the left.

=>A[] = {50, 60, 10, 20, 30, 40}

So, array A[] after right rotation by 2 positions: {50, 60, 10, 20, 30, 40}

## 1. C# program & output to Rotate an Array

Code has been copied
/*****************************
alphabetacoder.com
C# program to rotate an array
******************************/

using System;

namespace RotateArray {
class Program {
static void Main(string[] args) {
// declare variables
int i, j, k, s, d, e;

// take input
Console.Write("Enter the size of array: ");

// declare an array
int[] arr = new int[s];

// take input
Console.WriteLine("Enter the elements of array: ");
for (i = 0; i < s; i++) {
}

// take input of the direction of rotation
Console.WriteLine("Enter the direction of rotation: ");
Console.WriteLine("1. Left rotation");
Console.WriteLine("2. Right rotation");

switch (d)
{
case 1:
// take input of the number of position of rotation
Console.Write("Enter the number of position to be left shifted: ");

// left shift the array upto k position
for (i = 0; i < k; i++) {
// get the first elements
e = arr[0];
for (j = 0; j < s - 1; j++) {
arr[j] = arr[j + 1];
}
arr[s - 1] = e;
}
// display the array
Console.WriteLine("Output array: ");
for (i = 0; i < s; i++) {
Console.Write(arr[i] + " ");
}
break;
case 2:
// take input of the number of position of rotation
Console.Write("Enter the number of position to be right shifted: ");

// right shift the array upto k position
for (i = 0; i < k; i++) {
// get the first elements
e = arr[s - 1];
for (j = s - 1; j > 0; j--) {
arr[j] = arr[j - 1];
}
arr[0] = e;
}
// display the array
Console.WriteLine("Output array: ");
for (i = 0; i < s; i++) {
Console.Write(arr[i] + " ");
}
break;
default:
Console.WriteLine("Wrong choice!");
break;
}

// wait for the user to press any key
}
}
}


Output

#### Case 1:

Enter the size of array: 6

Enter the elements of array:

1

2

3

4

5

6

Enter the direction of rotation:

1. Left rotation

2. Right rotation

Enter the number of position to be right shifted: 2

Output array:

5 6 1 2 3 4

#### Case 2:

Enter the size of array: 6

Enter the elements of array:

1

2

3

4

5

6

Enter the direction of rotation:

1. Left rotation

2. Right rotation

Enter the number of position to be left shifted: 2

Output array:

3 4 5 6 1 2

## 2. Time complexity to Rotate an Array

Time Complexity: O(n * k)

Here, $n$ elements in an array are to be rotated by $k$ positions to either left or right.