The relation among divisor, dividend, quotient and remainder is *dividend = divisor * quotient + remainder*. ** C program to compute quotient and remainder** between two integers can be calculated by using the division ( / ) and modulus ( % ) operators respectively. To compute the remainder of the division of two floating-point numbers, the library function *fmod( )* is used. This function considers quotient as an integer number and the remainder as a floating-point number.

The following C programs compute the quotient and remainder of two numbers. The algorithm, pseudocode and time complexity of the program have also been mentioned. The flowchart of the problem has been shown **here**.

## 1. Algorithm to Compute Quotient and Remainder

1. Take two integers say $x,~y$ as input.

2. Compute the quotient $q= floor(\frac{x}{y})$

3. Compute the remainder $r= x \mod y$

4. Return $q, r$

## 2. Pseudocode to Compute Quotient and Remainder

**Input** : Two integer numbers $x,~y$

**Output** : Two integer numbers as quotient and remainder when $x$ is divided by $y$

1. **Procedure** quotientRemainder($x, y$):

2.

3.

4. **Return** $q,~r$

5. **End Procedure**

## 3. Time complexity to Compute Quotient and Remainder

**Time Complexity: ****O(1)**

## 4. C Program & output to Compute Quotient and Remainder

/****************************************** Alphabetacoder.com C program to compute quotient and remainder *******************************************/ #include <stdio.h> int main() { //initialize two variables int a = 17, b = 5; int q, r; //find the quotient q = a / b; //find the remainder r = a % b; printf("When %d is divided by %d, quotient is %d and remainder is %d.", a, b, q, r); return 0; }

Output

When 17 is divided by 5, quotient is 3 and remainder is 2.

## 5. C Program & output to Compute Remainder using fmod() function

/********************************** Alphabetacoder.com C program to compute the remainder using fmod() function ***********************************/ #include <stdio.h> #include <math.h> int main() { //initialize two variables float a = 17.5, b = 3.7; float r; //find the remainder using fmod() function r = fmod(a, b); printf("Remainder is %f", r); return 0; }

Output

Remainder is 2.700000

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